You may wonder if it’s possible to control a light using a remote controller. In this article CircuitsGallery presents an interesting DIY circuit that helps you to turn ON and OFF a lamp with a remote control.
Here we have made use of TSOP, an IR receiver which detects the IR rays from the remote. NE555 is the next important part which produces a clock pulse for toggling the D flip flop.The relay helps to connect any electrical devices to the circuit and you can control any electrical equipment, not only a light.
You must need regulated power supply of 5 volt to do this circuit because TSOP requires 5v. Its voltage should not exceed 5V.
You can use normal remote control of home appliances for this and of course I meant the one with Infra Red transmitter. Or else if you’re interested to make one of your own then it’s simple, just have a look at our simple IR transmitter and receiver circuit.
- Similar Circuit: Clap switch Circuit
Circuit Diagram of Remote Control Light
- 230v to 6v step down transformer
- 7805 voltage regulator
- TSOP IR receiver
- IC 555
- IC 7474
- BC 187 Transistor
- Diode 1N4007x5
- Resistors (220KΩ, 100Ω)
- Relay (6V)
- Capacitor (1μF, 470μF)
Working of Remote Control Light Switch
- Power supply circuit is not shown here. 1st you build a Rectifier circuit for 6v DC and proceed.
- Maximum voltage of TSOP and 7474 is 5V hence we are using 7805 voltage regulator IC to get constant 5V DC.
- The output of TSOP is always 5V, and the output will be zero when IR rays strikes on it.
- 555 IC biased as a Monostable Multivibrator. Normally its output is 0V (ground potential), provided that voltage at the 2nd pin must be greater than 1/3Vcc.
- When the voltage at the 2nd pin goes below 1/3Vcc output switches to high (5V) for the time T=1.1RC after the time interval output returns to 0V again.
- The D-flip flop7474 is wired as Toggle mode, i.e. Q’ to D input. 555 used as clock generator to the flip flop.
- When it get a clock pulse Output goes to High and remain in that state until it get next pulse.
- On receiving next pulse output goes to low and remain in that state till the next pulse.
- This process will continue.
- Output of 7474 is fed to base terminal of BC 187 which is driver transistor, when it base voltage is high current will flow through the load
- Here relay is the load and it will energize only when the base voltage of BC 187 is high and connects the 230v AC supply to the Bulb or light.
(Read More: How to Connect relay in circuit)
- Diode Df is freewheeling diode used to dissipate the stored energy in the inductor load. It is essential for the smooth working of this circuit
Circuit workout video
Here is the video demonstration showing working of the circuit. Enjoy…!